Solve left(3^2right)^3+left(3^3right)^3

$${ \left( { 3 }^{ 2 } \right) }^{ 3 } + { \left( { 3 }^{ 3 } \right) }^{ 3 }$$

Evaluate

$$20412$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$3^{6}+\left(3^{3}\right)^{3}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$3^{6}+3^{9}$$

Calculate 3 to the power of 6 and get 729.

$$729+3^{9}$$

Calculate 3 to the power of 9 and get 19683.

$$729+19683$$

Add 729 and 19683 to get 20412.

$$20412$$

Factor

$$2^{2}\times 3^{6}\times 7$$