Solve {left(10^2+4-sqrt{64}-2^4right)}^2+80010^2

$${ \left( { 10 }^{ 2 } +4- \sqrt{ 64 } - { 2 }^{ 4 } \right) }^{ 2 } +800 { 10 }^{ 2 }$$

Evaluate

$$86400$$

Solution Steps

Calculate 10 to the power of 2 and get 100.

$$\left(100+4-\sqrt{64}-2^{4}\right)^{2}+800\times 10^{2}$$

Add 100 and 4 to get 104.

$$\left(104-\sqrt{64}-2^{4}\right)^{2}+800\times 10^{2}$$

Calculate the square root of 64 and get 8.

$$\left(104-8-2^{4}\right)^{2}+800\times 10^{2}$$

Subtract 8 from 104 to get 96.

$$\left(96-2^{4}\right)^{2}+800\times 10^{2}$$

Calculate 2 to the power of 4 and get 16.

$$\left(96-16\right)^{2}+800\times 10^{2}$$

Subtract 16 from 96 to get 80.

$$80^{2}+800\times 10^{2}$$

Calculate 80 to the power of 2 and get 6400.

$$6400+800\times 10^{2}$$

Calculate 10 to the power of 2 and get 100.

$$6400+800\times 100$$

Multiply 800 and 100 to get 80000.

$$6400+80000$$

Add 6400 and 80000 to get 86400.

$$86400$$

Factor

$$2^{7}\times 3^{3}\times 5^{2}$$