Solve {left({left(27/27right)}^40right)}^2+6^2

$${ \left( { \left( \frac{ 27 }{ 27 } \right) }^{ 40 } \right) }^{ 2 } + { 6 }^{ 2 }$$

Evaluate

$$37$$

Solution Steps

Divide 27 by 27 to get 1.

$$\left(1^{40}\right)^{2}+6^{2}$$

To raise a power to another power, multiply the exponents. Multiply 40 and 2 to get 80.

$$1^{80}+6^{2}$$

Calculate 1 to the power of 80 and get 1.

$$1+6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$1+36$$

Add 1 and 36 to get 37.

$$37$$

Factor

$$37$$