Solve {left(sqrt{5}right)}^2*4x-52/58=6

$${ \left( \sqrt{ 5 } \right) }^{ 2 } \times 4x- \frac{ 52 }{ 58 } =6$$

Solve for x

$$x=\frac{10}{29}\approx 0.344827586$$

Steps for Solving Linear Equation

The square of \sqrt{5} is 5.

$$4\times 5x-\frac{52}{58}=6$$

Multiply 4 and 5 to get 20.

$$20x-\frac{52}{58}=6$$

Reduce the fraction \frac{52}{58} to lowest terms by extracting and canceling out 2.

$$20x-\frac{26}{29}=6$$

Add \frac{26}{29} to both sides.

$$20x=6+\frac{26}{29}$$

Add 6 and \frac{26}{29} to get \frac{200}{29}.

$$20x=\frac{200}{29}$$

Divide both sides by 20.

$$x=\frac{\frac{200}{29}}{20}$$

Express \frac{\frac{200}{29}}{20} as a single fraction.

$$x=\frac{200}{29\times 20}$$

Multiply 29 and 20 to get 580.

$$x=\frac{200}{580}$$

Reduce the fraction \frac{200}{580} to lowest terms by extracting and canceling out 20.

$$x=\frac{10}{29}$$