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\left(\sqrt{3}\right)^{2}-2\sqrt{3}+1+2\sqrt{3}+2-2
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-1\right)^{2}.
3-2\sqrt{3}+1+2\sqrt{3}+2-2
The square of \sqrt{3} is 3.
4-2\sqrt{3}+2\sqrt{3}+2-2
Add 3 and 1 to get 4.
4+2-2
Combine -2\sqrt{3} and 2\sqrt{3} to get 0.
6-2
Add 4 and 2 to get 6.
4
Subtract 2 from 6 to get 4.