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\left(\frac{1}{\cos(x)}-\tan(x)\right)\left(\frac{1}{\cos(x)}+\tan(x)\right)
The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{1-\sin(x)}{\cos(x)}
Consider \frac{1}{\cos(x)}-\tan(x). Factor out \frac{1}{\cos(x)}.
\frac{1+\sin(x)}{\cos(x)}
Consider \frac{1}{\cos(x)}+\tan(x). Factor out \frac{1}{\cos(x)}.
\left(1-\sin(x)\right)\left(1+\sin(x)\right)\times \left(\frac{1}{\cos(x)}\right)^{2}
Rewrite the complete factored expression.