Solve {left(8/3sqrt{3}right)}^2-16

$${ \left( \frac{ 8 }{ 3 } \sqrt{ 3 } \right) }^{ 2 } -16$$

Evaluate

$$\frac{16}{3}\approx 5.333333333$$

Solution Steps

Expand \left(\frac{8}{3}\sqrt{3}\right)^{2}.

$$\left(\frac{8}{3}\right)^{2}\left(\sqrt{3}\right)^{2}-16$$

Calculate \frac{8}{3} to the power of 2 and get \frac{64}{9}.

$$\frac{64}{9}\left(\sqrt{3}\right)^{2}-16$$

The square of \sqrt{3} is 3.

$$\frac{64}{9}\times 3-16$$

Multiply \frac{64}{9} and 3 to get \frac{64}{3}.

$$\frac{64}{3}-16$$

Subtract 16 from \frac{64}{3} to get \frac{16}{3}.

$$\frac{16}{3}$$

Factor

$$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$$