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\left(\frac{11}{12}+\frac{1}{2}\right)^{-3}
Subtract \frac{1}{3} from \frac{5}{4} to get \frac{11}{12}.
\left(\frac{17}{12}\right)^{-3}
Add \frac{11}{12} and \frac{1}{2} to get \frac{17}{12}.
\frac{1728}{4913}
Calculate \frac{17}{12} to the power of -3 and get \frac{1728}{4913}.