Solve {left(4/3right)}^3-{left(7/2right)}^2=

$${ \left( \frac{ 4 }{ 3 } \right) }^{ 3 } - { \left( \frac{ 7 }{ 2 } \right) }^{ 2 } =$$

Evaluate

$$-\frac{1067}{108}\approx -9.87962963$$

Solution Steps

Calculate \frac{4}{3} to the power of 3 and get \frac{64}{27}.

$$\frac{64}{27}-\left(\frac{7}{2}\right)^{2}$$

Calculate \frac{7}{2} to the power of 2 and get \frac{49}{4}.

$$\frac{64}{27}-\frac{49}{4}$$

Least common multiple of 27 and 4 is 108. Convert \frac{64}{27} and \frac{49}{4} to fractions with denominator 108.

$$\frac{256}{108}-\frac{1323}{108}$$

Since \frac{256}{108} and \frac{1323}{108} have the same denominator, subtract them by subtracting their numerators.

$$\frac{256-1323}{108}$$

Subtract 1323 from 256 to get -1067.

$$-\frac{1067}{108}$$

Factor

$$-\frac{1067}{108} = -9\frac{95}{108} = -9.87962962962963$$