Solve {left(28/3right)}^2-16^2

$${ \left( \frac{ 28 }{ 3 } \right) }^{ 2 } - { 16 }^{ 2 }$$

Evaluate

$$-\frac{1520}{9}\approx -168.888888889$$

Solution Steps

Calculate \frac{28}{3} to the power of 2 and get \frac{784}{9}.

$$\frac{784}{9}-16^{2}$$

Calculate 16 to the power of 2 and get 256.

$$\frac{784}{9}-256$$

Convert 256 to fraction \frac{2304}{9}.

$$\frac{784}{9}-\frac{2304}{9}$$

Since \frac{784}{9} and \frac{2304}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{784-2304}{9}$$

Subtract 2304 from 784 to get -1520.

$$-\frac{1520}{9}$$

Factor

$$-\frac{1520}{9} = -168\frac{8}{9} = -168.88888888888889$$