Solve {left(25/3right)}^2-{left(20/3right)}^2=

$${ \left( \frac{ 25 }{ 3 } \right) }^{ 2 } - { \left( \frac{ 20 }{ 3 } \right) }^{ 2 } =$$

Evaluate

$$25$$

Solution Steps

Calculate \frac{25}{3} to the power of 2 and get \frac{625}{9}.

$$\frac{625}{9}-\left(\frac{20}{3}\right)^{2}$$

Calculate \frac{20}{3} to the power of 2 and get \frac{400}{9}.

$$\frac{625}{9}-\frac{400}{9}$$

Since \frac{625}{9} and \frac{400}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{625-400}{9}$$

Subtract 400 from 625 to get 225.

$$\frac{225}{9}$$

Divide 225 by 9 to get 25.

$$25$$

Factor

$$5^{2}$$