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\frac{1}{8}+\frac{3}{4}x+\frac{3}{2}x^{2}+x^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(\frac{1}{2}+x\right)^{3}.
\frac{1}{8}+\frac{3}{4}x+\frac{3}{2}x^{2}+x^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(\frac{1}{2}+x\right)^{3}.