Evaluate
\frac{1875}{493}\approx 3.803245436
Factor
\frac{3 \cdot 5 ^ {4}}{17 \cdot 29} = 3\frac{396}{493} = 3.8032454361054766
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\left(\frac{79}{300}-\frac{1}{2500}\right)^{-1}
Expand \frac{0.079}{0.3} by multiplying both numerator and the denominator by 1000.
\left(\frac{493}{1875}\right)^{-1}
Subtract \frac{1}{2500} from \frac{79}{300} to get \frac{493}{1875}.
\frac{1875}{493}
Calculate \frac{493}{1875} to the power of -1 and get \frac{1875}{493}.
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