Solve {left(2^9/left(2^22right)^3right)}^-3

$${ \left( \frac{ { 2 }^{ 9 } }{ { \left( { 2 }^{ 2 } 2 \right) }^{ 3 } } \right) }^{ -3 }$$

Evaluate

$$1$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\left(\frac{2^{9}}{\left(2^{3}\right)^{3}}\right)^{-3}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$\left(\frac{2^{9}}{2^{9}}\right)^{-3}$$

Divide 2^{9} by 2^{9} to get 1.

$$1^{-3}$$

Calculate 1 to the power of -3 and get 1.

$$1$$

Factor

$$1$$