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x^{3}-3x^{2}\sqrt{-2}+3x\left(\sqrt{-2}\right)^{2}-\left(\sqrt{-2}\right)^{3}
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-\sqrt{-2}\right)^{3}.
x^{3}-3x^{2}\sqrt{-2}+3x\left(-2\right)-\left(\sqrt{-2}\right)^{3}
Calculate \sqrt{-2} to the power of 2 and get -2.
x^{3}-3x^{2}\sqrt{-2}-6x-\left(\sqrt{-2}\right)^{3}
Multiply 3 and -2 to get -6.