Solve for y
\left\{\begin{matrix}y=-\frac{\left(x-3\right)x^{2}}{\xi }\text{, }&\xi \neq 0\\y\in \mathrm{R}\text{, }&\left(x=0\text{ or }x=3\right)\text{ and }\xi =0\end{matrix}\right.
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\xi y=3x^{2}-x^{3}
The equation is in standard form.
\frac{\xi y}{\xi }=\frac{\left(3-x\right)x^{2}}{\xi }
Divide both sides by \xi .
y=\frac{\left(3-x\right)x^{2}}{\xi }
Dividing by \xi undoes the multiplication by \xi .
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