Solve θsqrt{36}+31/3

$$\theta \sqrt { 36 } + 3 \frac { 1 } { 3 }$$

Evaluate

$$6\theta +\frac{10}{3}$$

Solution Steps

Calculate the square root of 36 and get 6.

$$\theta \times 6+\frac{3\times 3+1}{3}$$

Multiply 3 and 3 to get 9.

$$\theta \times 6+\frac{9+1}{3}$$

Add 9 and 1 to get 10.

$$\theta \times 6+\frac{10}{3}$$

Factor

$$\frac{2\left(9\theta +5\right)}{3}$$

Solution Steps

Calculate the square root of 36 and get 6.

$$factor(\theta \times 6+\frac{3\times 3+1}{3})$$

Multiply 3 and 3 to get 9.

$$factor(\theta \times 6+\frac{9+1}{3})$$

Add 9 and 1 to get 10.

$$factor(\theta \times 6+\frac{10}{3})$$

Factor out \frac{2}{3}.

$$\frac{2\left(9\theta +5\right)}{3}$$