Solve θ=operatorname{arcos}3/5

$$\theta = \operatorname { arcos } \frac { 3 } { 5 }$$

Solve for a

$$\left\{\begin{matrix}a=\frac{\theta }{\cos(\frac{3}{5})r}\text{, }&r\neq 0\\a\in \mathrm{R}\text{, }&\theta =0\text{ and }r=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$ar\cos(\frac{3}{5})=\theta$$

The equation is in standard form.

$$\cos(\frac{3}{5})ra=\theta$$

Divide both sides by r\cos(\frac{3}{5}).

$$\frac{\cos(\frac{3}{5})ra}{\cos(\frac{3}{5})r}=\frac{\theta }{\cos(\frac{3}{5})r}$$

Dividing by r\cos(\frac{3}{5}) undoes the multiplication by r\cos(\frac{3}{5}).

$$a=\frac{\theta }{\cos(\frac{3}{5})r}$$

Solve for r

$$\left\{\begin{matrix}r=\frac{\theta }{\cos(\frac{3}{5})a}\text{, }&a\neq 0\\r\in \mathrm{R}\text{, }&\theta =0\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$ar\cos(\frac{3}{5})=\theta$$

The equation is in standard form.

$$\cos(\frac{3}{5})ar=\theta$$

Divide both sides by a\cos(\frac{3}{5}).

$$\frac{\cos(\frac{3}{5})ar}{\cos(\frac{3}{5})a}=\frac{\theta }{\cos(\frac{3}{5})a}$$

Dividing by a\cos(\frac{3}{5}) undoes the multiplication by a\cos(\frac{3}{5}).

$$r=\frac{\theta }{\cos(\frac{3}{5})a}$$