Solve θ=5-2i/5i

$$\theta = \frac { 5 - 2 i } { 5 i }$$

Solve for θ

$$\theta =-\frac{2}{5}-i=-0.4-i$$

Steps for Solving Linear Equation

Multiply both numerator and denominator of \frac{5-2i}{5i} by imaginary unit i.

$$\theta =\frac{\left(5-2i\right)i}{5i^{2}}$$

By definition, i^{2} is -1. Calculate the denominator.

$$\theta =\frac{\left(5-2i\right)i}{-5}$$

Multiply 5-2i times i.

$$\theta =\frac{5i-2i^{2}}{-5}$$

By definition, i^{2} is -1.

$$\theta =\frac{5i-2\left(-1\right)}{-5}$$

Do the multiplications in 5i-2\left(-1\right). Reorder the terms.

$$\theta =\frac{2+5i}{-5}$$

Divide 2+5i by -5 to get -\frac{2}{5}-i.

$$\theta =-\frac{2}{5}-i$$

Assign θ

$$\theta ≔-\frac{2}{5}-i$$