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\theta =1\times \frac{-6}{\sqrt{10}}
Anything divided by one gives itself.
\theta =1\times \frac{-6\sqrt{10}}{\left(\sqrt{10}\right)^{2}}
Rationalize the denominator of \frac{-6}{\sqrt{10}} by multiplying numerator and denominator by \sqrt{10}.
\theta =1\times \frac{-6\sqrt{10}}{10}
The square of \sqrt{10} is 10.
\theta =1\left(-\frac{3}{5}\right)\sqrt{10}
Divide -6\sqrt{10} by 10 to get -\frac{3}{5}\sqrt{10}.
\theta =-\frac{3}{5}\sqrt{10}
Multiply 1 and -\frac{3}{5} to get -\frac{3}{5}.