Solve θ=frac{sqrt{3}}{2} | Microsoft Math Solver

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Solve for θ

θ = \frac{3}{2} \approx 0.866025404

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θ : = \frac{3}{2}

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θ = \frac{3}{2}

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Alternative of finding theta when sin

θ

θ

https://math.stackexchange.com/questions/929514/alternative-of-finding-theta-when-sin-theta-and-cos-theta-are-given

sin θ = \frac{3}{2} = sin \frac{π}{3} ⟹ θ = n π + (- 1)^{n} \frac{π}{3}

n

is any integer Set

n = 2 s + 1,

= 2 s

(even) one by one Again,

cos θ = - \frac{1}{2} = - cos \frac{π}{3} = cos (π - \frac{π}{3})

Delta-method for the convergence in distribution of

a_{n} (h (\overset{ˉ}{X}_{n}) - h (θ) - b_{n})

h^{'} (θ) = 0

https://math.stackexchange.com/questions/2377042/delta-method-for-the-convergence-in-distribution-of-a-n-lefth-bar-x-n-h-t

The so-called delta-method stems from two basic results: By the usual CLT,

n (\overset{ˉ}{X}_{n} - θ) \to σ_{θ} Z

in distribution, where

Z

is standard normal and

σ_{θ}^{2} = v a r (X_{1})

Proof convergence of vectors

https://math.stackexchange.com/questions/2948414/proof-convergence-of-vectors

I give here both if part and only if part. Let

{a_{k}}_{k}

a

R^{n}

. Then using norm

∣ ∣ . ∣ ∣

R^{n}

we can say that given any

ϵ > 0

(- 1)^{⌊ n θ ⌋}

θ

is an irrational number)?

https://math.stackexchange.com/questions/2986901/how-to-analyze-1-left-lfloor-n-theta-right-rfloor-in-which-theta

This is a very interesting problem. Throughout this proof, let

ρ (x, z) = \sum_{n = 1}^{x} (- 1)^{⌊ \frac{n}{φ} + z ⌋},

x \in N

z \in R

Find an Unbiased Estimator of a Function of a Parameter [duplicate]

https://math.stackexchange.com/q/2643604

\hat{β} = \frac{1 - θ ^}{3 n} .

Then as you have shown

E \hat{β} = \frac{1 - θ}{3 n} .

\hat{β}

is an unbiased estimator of

\frac{1 - θ}{3 n}

Approximation of irrational numbers?

https://math.stackexchange.com/questions/1364605/approximation-of-irrational-numbers

φ = (5 + 1) / 2

(which is a root of

x^{2} - x - 1

F_{n}

are the Fibonacci numbers,

∣ F_{n} - φ F_{n - 1} ∣

0

exponentially. Take

a_{n} = F_{n + k}

for sufficiently ...

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