Solve θ+a=pi/6pi8.(sqrt{3}+tanθ)(sqrt{3}+tanalpha)=4

$$\theta + a = \frac { \pi } { 6 } \pi 8 . ( \sqrt { 3 } + \tan \theta ) ( \sqrt { 3 } + \tan \alpha ) = 4$$

Solve for a

$$a=-\theta +\frac{4\pi ^{2}}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$6\theta +6a=\pi \pi \times 8$$

Multiply \pi and \pi to get \pi ^{2}.

$$6\theta +6a=\pi ^{2}\times 8$$

Subtract 6\theta from both sides.

$$6a=\pi ^{2}\times 8-6\theta$$

The equation is in standard form.

$$6a=8\pi ^{2}-6\theta$$

Divide both sides by 6.

$$\frac{6a}{6}=\frac{8\pi ^{2}-6\theta }{6}$$

Dividing by 6 undoes the multiplication by 6.

$$a=\frac{8\pi ^{2}-6\theta }{6}$$

Divide 8\pi ^{2}-6\theta by 6.

$$a=-\theta +\frac{4\pi ^{2}}{3}$$

Solve for θ

$$\theta =-a+\frac{4\pi ^{2}}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6.

$$6\theta +6a=\pi \pi \times 8$$

Multiply \pi and \pi to get \pi ^{2}.

$$6\theta +6a=\pi ^{2}\times 8$$

Subtract 6a from both sides.

$$6\theta =\pi ^{2}\times 8-6a$$

The equation is in standard form.

$$6\theta =8\pi ^{2}-6a$$

Divide both sides by 6.

$$\frac{6\theta }{6}=\frac{8\pi ^{2}-6a}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$\theta =\frac{8\pi ^{2}-6a}{6}$$

Divide 8\pi ^{2}-6a by 6.

$$\theta =-a+\frac{4\pi ^{2}}{3}$$