Solve θx-44=tan(x^2*sqrt{sqrt[3]{3x+7}})

$$\theta x-44= \tan ( { x }^{ 2 } \times \sqrt{ \sqrt[3]{ 3x+7 } } )$$

Solve for θ

$$\theta =\frac{\sin(\sqrt[6]{3x+7}x^{2})+44\cos(\sqrt[6]{3x+7}x^{2})}{x\cos(\sqrt[6]{3x+7}x^{2})}$$

$$x\neq 0\text{ and }x\geq -\frac{7}{3}\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }\sqrt[6]{3x+7}x^{2}=\pi n_{1}+\frac{\pi }{2}$$

Steps for Solving Linear Equation

Add 44 to both sides.

$$\theta x=\tan(x^{2}\sqrt{\sqrt[3]{3x+7}})+44$$

The equation is in standard form.

$$x\theta =\tan(\sqrt{\sqrt[3]{3x+7}}x^{2})+44$$

Divide both sides by x.

$$\frac{x\theta }{x}=\frac{\tan(\sqrt[6]{3x+7}x^{2})+44}{x}$$

Dividing by x undoes the multiplication by x.

$$\theta =\frac{\tan(\sqrt[6]{3x+7}x^{2})+44}{x}$$