Solve θpi0sqrt{sqrt[7]{8}}x^2-4x-5=0

$$\theta \pi 0 \sqrt{ \sqrt[ 7 ]{ 8 } } { x }^{ 2 } -4x-5 = 0$$

Solve for x

$$x = -\frac{5}{4} = -1\frac{1}{4} = -1.25$$

Steps for Solving Linear Equation

Add 5 to both sides. Anything plus zero gives itself.

$$0\theta \pi \sqrt{\sqrt[7]{8}}x^{2}-4x=5$$

Reorder the terms.

$$-4x=5$$

Divide both sides by -4.

$$x=\frac{5}{-4}$$

Fraction \frac{5}{-4} can be rewritten as -\frac{5}{4} by extracting the negative sign.

$$x=-\frac{5}{4}$$

Solve for θ (complex solution)

$$\theta \in \mathrm{C}$$

$$x = -\frac{5}{4} = -1\frac{1}{4} = -1.25$$

Solve for θ

$$\theta \in \mathrm{R}$$

$$x = -\frac{5}{4} = -1\frac{1}{4} = -1.25$$