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\tan(180+30)=\frac{\tan(180)+\tan(30)}{1-\tan(180)\tan(30)}
Use \tan(x+y)=\frac{\tan(x)+\tan(y)}{1-\tan(x)\tan(y)} where x=180 and y=30 to obtain the result.
\frac{0+\tan(30)}{1-0\tan(30)}
Get the value of \tan(180) from trigonometric values table. Replace the value in both the numerator and the denominator.
\frac{0+\frac{\sqrt{3}}{3}}{1-0\times \frac{\sqrt{3}}{3}}
Get the value of \tan(30) from trigonometric values table. Replace the value in both the numerator and the denominator.
\frac{\sqrt{3}}{3}
Do the calculations.