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\tan(180+45)=\frac{\tan(180)+\tan(45)}{1-\tan(180)\tan(45)}
Use \tan(x+y)=\frac{\tan(x)+\tan(y)}{1-\tan(x)\tan(y)} where x=180 and y=45 to obtain the result.
\frac{0+\tan(45)}{1-0\tan(45)}
Get the value of \tan(180) from trigonometric values table. Replace the value in both the numerator and the denominator.
\frac{0+1}{1-0\times 1}
Get the value of \tan(45) from trigonometric values table. Replace the value in both the numerator and the denominator.
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