Solve for R
\left\{\begin{matrix}R=-\frac{4}{y\cos(\alpha )}\text{, }&y\neq 0\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }\alpha =\pi n_{1}+\frac{\pi }{2}\\R\in \mathrm{R}\text{, }&\exists n_{2}\in \mathrm{Z}\text{ : }\alpha =\pi n_{2}\end{matrix}\right.
Solve for y
\left\{\begin{matrix}y=-\frac{4}{R\cos(\alpha )}\text{, }&R\neq 0\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }\alpha =\pi n_{1}+\frac{\pi }{2}\\y\in \mathrm{R}\text{, }&\exists n_{2}\in \mathrm{Z}\text{ : }\alpha =\pi n_{2}\end{matrix}\right.
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\tan(\alpha )=-\frac{1}{4}Ry\sin(\alpha )
Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.
-\frac{1}{4}Ry\sin(\alpha )=\tan(\alpha )
Swap sides so that all variable terms are on the left hand side.
\left(-\frac{y\sin(\alpha )}{4}\right)R=\tan(\alpha )
The equation is in standard form.
\frac{\left(-\frac{y\sin(\alpha )}{4}\right)R}{-\frac{y\sin(\alpha )}{4}}=\frac{\tan(\alpha )}{-\frac{y\sin(\alpha )}{4}}
Divide both sides by -\frac{1}{4}y\sin(\alpha ).
R=\frac{\tan(\alpha )}{-\frac{y\sin(\alpha )}{4}}
Dividing by -\frac{1}{4}y\sin(\alpha ) undoes the multiplication by -\frac{1}{4}y\sin(\alpha ).
R=-\frac{4}{y\cos(\alpha )}
Divide \tan(\alpha ) by -\frac{1}{4}y\sin(\alpha ).
\tan(\alpha )=-\frac{1}{4}Ry\sin(\alpha )
Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.
-\frac{1}{4}Ry\sin(\alpha )=\tan(\alpha )
Swap sides so that all variable terms are on the left hand side.
\left(-\frac{R\sin(\alpha )}{4}\right)y=\tan(\alpha )
The equation is in standard form.
\frac{\left(-\frac{R\sin(\alpha )}{4}\right)y}{-\frac{R\sin(\alpha )}{4}}=\frac{\tan(\alpha )}{-\frac{R\sin(\alpha )}{4}}
Divide both sides by -\frac{1}{4}R\sin(\alpha ).
y=\frac{\tan(\alpha )}{-\frac{R\sin(\alpha )}{4}}
Dividing by -\frac{1}{4}R\sin(\alpha ) undoes the multiplication by -\frac{1}{4}R\sin(\alpha ).
y=-\frac{4}{R\cos(\alpha )}
Divide \tan(\alpha ) by -\frac{1}{4}R\sin(\alpha ).
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