Solve sump=q(3^5-1/3-1)

$$\sum p = q ( \frac { 3 ^ { 5 } - 1 } { 3 - 1 } )$$

Solve for p

$$\left\{\begin{matrix}p=\frac{121q}{Σ}\text{, }&Σ\neq 0\\p\in \mathrm{R}\text{, }&q=0\text{ and }Σ=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Calculate 3 to the power of 5 and get 243.

$$Σp=q\times \frac{243-1}{3-1}$$

Subtract 1 from 243 to get 242.

$$Σp=q\times \frac{242}{3-1}$$

Subtract 1 from 3 to get 2.

$$Σp=q\times \frac{242}{2}$$

Divide 242 by 2 to get 121.

$$Σp=q\times 121$$

The equation is in standard form.

$$Σp=121q$$

Divide both sides by Σ.

$$\frac{Σp}{Σ}=\frac{121q}{Σ}$$

Dividing by Σ undoes the multiplication by Σ.

$$p=\frac{121q}{Σ}$$

Solve for q

$$q=\frac{pΣ}{121}$$

Steps for Solving Linear Equation

Calculate 3 to the power of 5 and get 243.

$$Σp=q\times \frac{243-1}{3-1}$$

Subtract 1 from 243 to get 242.

$$Σp=q\times \frac{242}{3-1}$$

Subtract 1 from 3 to get 2.

$$Σp=q\times \frac{242}{2}$$

Divide 242 by 2 to get 121.

$$Σp=q\times 121$$

Swap sides so that all variable terms are on the left hand side.

$$q\times 121=Σp$$

The equation is in standard form.

$$121q=pΣ$$

Divide both sides by 121.

$$\frac{121q}{121}=\frac{pΣ}{121}$$

Dividing by 121 undoes the multiplication by 121.

$$q=\frac{pΣ}{121}$$