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Solve for x (complex solution)
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\left(\sqrt{x-5}\right)^{2}=\left(\sqrt{2x-7}\right)^{2}
Square both sides of the equation.
x-5=\left(\sqrt{2x-7}\right)^{2}
Calculate \sqrt{x-5} to the power of 2 and get x-5.
x-5=2x-7
Calculate \sqrt{2x-7} to the power of 2 and get 2x-7.
x-5-2x=-7
Subtract 2x from both sides.
-x-5=-7
Combine x and -2x to get -x.
-x=-7+5
Add 5 to both sides.
-x=-2
Add -7 and 5 to get -2.
x=2
Multiply both sides by -1.
\sqrt{2-5}=\sqrt{2\times 2-7}
Substitute 2 for x in the equation \sqrt{x-5}=\sqrt{2x-7}.
i\times 3^{\frac{1}{2}}=i\times 3^{\frac{1}{2}}
Simplify. The value x=2 satisfies the equation.
x=2
Equation \sqrt{x-5}=\sqrt{2x-7} has a unique solution.