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\left(\sqrt{x+15}\right)^{2}=\left(\sqrt{3x+1}\right)^{2}
Square both sides of the equation.
x+15=\left(\sqrt{3x+1}\right)^{2}
Calculate \sqrt{x+15} to the power of 2 and get x+15.
x+15=3x+1
Calculate \sqrt{3x+1} to the power of 2 and get 3x+1.
x+15-3x=1
Subtract 3x from both sides.
-2x+15=1
Combine x and -3x to get -2x.
-2x=1-15
Subtract 15 from both sides.
-2x=-14
Subtract 15 from 1 to get -14.
x=\frac{-14}{-2}
Divide both sides by -2.
x=7
Divide -14 by -2 to get 7.
\sqrt{7+15}=\sqrt{3\times 7+1}
Substitute 7 for x in the equation \sqrt{x+15}=\sqrt{3x+1}.
22^{\frac{1}{2}}=22^{\frac{1}{2}}
Simplify. The value x=7 satisfies the equation.
x=7
Equation \sqrt{x+15}=\sqrt{3x+1} has a unique solution.