Solve for x
x=\left(12-y\right)^{2}
12-y\geq 0
Solve for x (complex solution)
x=\left(12-y\right)^{2}
y=12\text{ or }arg(12-y)<\pi
Solve for y (complex solution)
y=-\sqrt{x}+12
Solve for y
y=-\sqrt{x}+12
x\geq 0
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\sqrt{x}+y-y=12-y
Subtract y from both sides of the equation.
\sqrt{x}=12-y
Subtracting y from itself leaves 0.
x=\left(12-y\right)^{2}
Square both sides of the equation.
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