Solve sqrt{x}+(y+3)=0

$$\sqrt{ x } +(y+3)=0$$

Solve for x

$$x=\left(y+3\right)^{2}$$

$$-\left(y+3\right)\geq 0$$

Steps for Solving Radical Equations

Subtract y+3 from both sides of the equation.

$$\sqrt{x}+y+3-\left(y+3\right)=-\left(y+3\right)$$

Subtracting y+3 from itself leaves 0.

$$\sqrt{x}=-\left(y+3\right)$$

Square both sides of the equation.

$$x=\left(y+3\right)^{2}$$

Solve for x (complex solution)

$$x=\left(y+3\right)^{2}$$

$$y=-3\text{ or }arg(y+3)\geq \pi$$

Solve for y (complex solution)

$$y=-\left(\sqrt{x}+3\right)$$

Solve for y

$$y=-\left(\sqrt{x}+3\right)$$

$$x\geq 0$$