Solve sqrt{9}-3-2+sqrt{3}-sqrt{9/4}=

$$\sqrt{ 9 } -3-2+ \sqrt{ 3 } - \sqrt{ \frac{ 9 }{ 4 } } =$$

Evaluate

$$\sqrt{3}-\frac{7}{2}\approx -1.767949192$$

Solution Steps

Calculate the square root of 9 and get 3.

$$3-3-2+\sqrt{3}-\sqrt{\frac{9}{4}}$$

Subtract 3 from 3 to get 0.

$$-2+\sqrt{3}-\sqrt{\frac{9}{4}}$$

Rewrite the square root of the division \frac{9}{4} as the division of square roots \frac{\sqrt{9}}{\sqrt{4}}. Take the square root of both numerator and denominator.

$$-2+\sqrt{3}-\frac{3}{2}$$

Convert -2 to fraction -\frac{4}{2}.

$$-\frac{4}{2}+\sqrt{3}-\frac{3}{2}$$

Since -\frac{4}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-3}{2}+\sqrt{3}$$

Subtract 3 from -4 to get -7.

$$-\frac{7}{2}+\sqrt{3}$$