Solve sqrt{9}+{left(sqrt{3}right)}^2+sqrt[3]{-8}

$$\sqrt{ 9 } + { \left( \sqrt{ 3 } \right) }^{ 2 } + \sqrt[ 3 ]{ -8 }$$

Evaluate

$$4$$

Solution Steps

Calculate the square root of 9 and get 3.

$$3+\left(\sqrt{3}\right)^{2}+\sqrt[3]{-8}$$

The square of \sqrt{3} is 3.

$$3+3+\sqrt[3]{-8}$$

Add 3 and 3 to get 6.

$$6+\sqrt[3]{-8}$$

Calculate \sqrt[3]{-8} and get -2.

$$6-2$$

Subtract 2 from 6 to get 4.

$$4$$

Factor

$$2^{2}$$