Solve for x
x = \frac{41}{4} = 10\frac{1}{4} = 10.25
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8x-81=1
Square both sides of the equation.
8x-81-\left(-81\right)=1-\left(-81\right)
Add 81 to both sides of the equation.
8x=1-\left(-81\right)
Subtracting -81 from itself leaves 0.
8x=82
Subtract -81 from 1.
\frac{8x}{8}=\frac{82}{8}
Divide both sides by 8.
x=\frac{82}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{41}{4}
Reduce the fraction \frac{82}{8} to lowest terms by extracting and canceling out 2.
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