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2\sqrt{2}-2\sin(45)+1-\frac{1}{3}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
2\sqrt{2}-2\times \frac{\sqrt{2}}{2}+1-\frac{1}{3}
Get the value of \sin(45) from trigonometric values table.
2\sqrt{2}-\sqrt{2}+1-\frac{1}{3}
Cancel out 2 and 2.
\sqrt{2}+1-\frac{1}{3}
Combine 2\sqrt{2} and -\sqrt{2} to get \sqrt{2}.
\sqrt{2}+\frac{2}{3}
Subtract \frac{1}{3} from 1 to get \frac{2}{3}.