Solve sqrt{8}+sqrt{98}

$$\sqrt{ 8 } + \sqrt{ 98 }$$

Evaluate

$$9\sqrt{2}\approx 12.727922061$$

Solution Steps

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$2\sqrt{2}+\sqrt{98}$$

Factor 98=7^{2}\times 2. Rewrite the square root of the product \sqrt{7^{2}\times 2} as the product of square roots \sqrt{7^{2}}\sqrt{2}. Take the square root of 7^{2}.

$$2\sqrt{2}+7\sqrt{2}$$

Combine 2\sqrt{2} and 7\sqrt{2} to get 9\sqrt{2}.

$$9\sqrt{2}$$