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\sqrt{7}x+3\sqrt{7}=\sqrt{28}
Factor 63=3^{2}\times 7. Rewrite the square root of the product \sqrt{3^{2}\times 7} as the product of square roots \sqrt{3^{2}}\sqrt{7}. Take the square root of 3^{2}.
\sqrt{7}x+3\sqrt{7}=2\sqrt{7}
Factor 28=2^{2}\times 7. Rewrite the square root of the product \sqrt{2^{2}\times 7} as the product of square roots \sqrt{2^{2}}\sqrt{7}. Take the square root of 2^{2}.
\sqrt{7}x=2\sqrt{7}-3\sqrt{7}
Subtract 3\sqrt{7} from both sides.
\sqrt{7}x=-\sqrt{7}
Combine 2\sqrt{7} and -3\sqrt{7} to get -\sqrt{7}.
\frac{\sqrt{7}x}{\sqrt{7}}=-\frac{\sqrt{7}}{\sqrt{7}}
Divide both sides by \sqrt{7}.
x=-\frac{\sqrt{7}}{\sqrt{7}}
Dividing by \sqrt{7} undoes the multiplication by \sqrt{7}.
x=-1
Divide -\sqrt{7} by \sqrt{7}.