Solve sqrt{6561}+3x=18x/5-7

$$\sqrt{ 6561 } +3x= \frac{ 18x }{ 5 } -7$$

Solve for x

$$x = \frac{440}{3} = 146\frac{2}{3} \approx 146.666666667$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$5\sqrt{6561}+15x=18x-35$$

Calculate the square root of 6561 and get 81.

$$5\times 81+15x=18x-35$$

Multiply 5 and 81 to get 405.

$$405+15x=18x-35$$

Subtract 18x from both sides.

$$405+15x-18x=-35$$

Combine 15x and -18x to get -3x.

$$405-3x=-35$$

Subtract 405 from both sides.

$$-3x=-35-405$$

Subtract 405 from -35 to get -440.

$$-3x=-440$$

Divide both sides by -3.

$$x=\frac{-440}{-3}$$

Fraction \frac{-440}{-3} can be simplified to \frac{440}{3} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{440}{3}$$