Solve sqrt{64}-4^3div4+75div5^2+13

$$\sqrt{ 64 } - { 4 }^{ 3 } \div 4+75 \div { 5 }^{ 2 } +13$$

Evaluate

$$8$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$\sqrt{64}-4^{2}+\frac{75}{5^{2}}+13$$

Calculate the square root of 64 and get 8.

$$8-4^{2}+\frac{75}{5^{2}}+13$$

Calculate 4 to the power of 2 and get 16.

$$8-16+\frac{75}{5^{2}}+13$$

Subtract 16 from 8 to get -8.

$$-8+\frac{75}{5^{2}}+13$$

Calculate 5 to the power of 2 and get 25.

$$-8+\frac{75}{25}+13$$

Divide 75 by 25 to get 3.

$$-8+3+13$$

Add -8 and 3 to get -5.

$$-5+13$$

Add -5 and 13 to get 8.

$$8$$

Factor

$$2^{3}$$