Solve sqrt{63^2+36.37^2}

$$\sqrt{ 6 { 3 }^{ 2 } +36. { 37 }^{ 2 } }$$

Evaluate

$$3\sqrt{5482}\approx 222.121588325$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\sqrt{6\times 9+36\times 37^{2}}$$

Multiply 6 and 9 to get 54.

$$\sqrt{54+36\times 37^{2}}$$

Calculate 37 to the power of 2 and get 1369.

$$\sqrt{54+36\times 1369}$$

Multiply 36 and 1369 to get 49284.

$$\sqrt{54+49284}$$

Add 54 and 49284 to get 49338.

$$\sqrt{49338}$$

Factor 49338=3^{2}\times 5482. Rewrite the square root of the product \sqrt{3^{2}\times 5482} as the product of square roots \sqrt{3^{2}}\sqrt{5482}. Take the square root of 3^{2}.

$$3\sqrt{5482}$$