Solve sqrt{468}+sqrt{268}=

$$\sqrt{ 468 } + \sqrt{ 268 } =$$

Evaluate

$$2\left(\sqrt{67}+3\sqrt{13}\right)\approx 38.004013197$$

Solution Steps

Factor 468=6^{2}\times 13. Rewrite the square root of the product \sqrt{6^{2}\times 13} as the product of square roots \sqrt{6^{2}}\sqrt{13}. Take the square root of 6^{2}.

$$6\sqrt{13}+\sqrt{268}$$

Factor 268=2^{2}\times 67. Rewrite the square root of the product \sqrt{2^{2}\times 67} as the product of square roots \sqrt{2^{2}}\sqrt{67}. Take the square root of 2^{2}.

$$6\sqrt{13}+2\sqrt{67}$$