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\left(\sqrt{3x+4}\right)^{2}=\left(\sqrt{2x+5}\right)^{2}
Square both sides of the equation.
3x+4=\left(\sqrt{2x+5}\right)^{2}
Calculate \sqrt{3x+4} to the power of 2 and get 3x+4.
3x+4=2x+5
Calculate \sqrt{2x+5} to the power of 2 and get 2x+5.
3x+4-2x=5
Subtract 2x from both sides.
x+4=5
Combine 3x and -2x to get x.
x=5-4
Subtract 4 from both sides.
x=1
Subtract 4 from 5 to get 1.
\sqrt{3\times 1+4}=\sqrt{2\times 1+5}
Substitute 1 for x in the equation \sqrt{3x+4}=\sqrt{2x+5}.
7^{\frac{1}{2}}=7^{\frac{1}{2}}
Simplify. The value x=1 satisfies the equation.
x=1
Equation \sqrt{3x+4}=\sqrt{2x+5} has a unique solution.