Solve for x
x=\frac{\left(9y-4z\right)^{2}}{3}
9y-4z\geq 0
Solve for x (complex solution)
x=\frac{\left(9y-4z\right)^{2}}{3}
y=\frac{4z}{9}\text{ or }arg(9y-4z)<\pi
Solve for y (complex solution)
y=\frac{4z+\sqrt{3x}}{9}
Solve for y
y=\frac{4z+\sqrt{3x}}{9}
x\geq 0
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3x=\left(9y-4z\right)^{2}
Square both sides of the equation.
\frac{3x}{3}=\frac{\left(9y-4z\right)^{2}}{3}
Divide both sides by 3.
x=\frac{\left(9y-4z\right)^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
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