Solve sqrt{3}x=y+40/3

$$\sqrt{ 3 } x= \frac{ y+40 }{ 3 }$$

Solve for x

$$x=\frac{\sqrt{3}\left(y+40\right)}{9}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$3\sqrt{3}x=y+40$$

Divide both sides by 3\sqrt{3}.

$$\frac{3\sqrt{3}x}{3\sqrt{3}}=\frac{y+40}{3\sqrt{3}}$$

Dividing by 3\sqrt{3} undoes the multiplication by 3\sqrt{3}.

$$x=\frac{y+40}{3\sqrt{3}}$$

Divide y+40 by 3\sqrt{3}.

$$x=\frac{\sqrt{3}\left(y+40\right)}{9}$$

Solve for y

$$y=3\sqrt{3}x-40$$

Solution Steps

Multiply both sides of the equation by 3.

$$3\sqrt{3}x=y+40$$

Swap sides so that all variable terms are on the left hand side.

$$y+40=3\sqrt{3}x$$

Subtract 40 from both sides.

$$y=3\sqrt{3}x-40$$