Solve sqrt{3}2-sqrt{5}0+sqrt{162}

$$\sqrt{ 3 } 2- \sqrt{ 5 } 0+ \sqrt{ 162 }$$

Evaluate

$$\sqrt{2}\left(\sqrt{6}+9\right)\approx 16.192023676$$

Solution Steps

Anything times zero gives zero.

$$2\sqrt{3}-0+\sqrt{162}$$

Factor 162=9^{2}\times 2. Rewrite the square root of the product \sqrt{9^{2}\times 2} as the product of square roots \sqrt{9^{2}}\sqrt{2}. Take the square root of 9^{2}.

$$2\sqrt{3}-0+9\sqrt{2}$$

Multiply -1 and 0 to get 0.

$$2\sqrt{3}+0+9\sqrt{2}$$

Anything plus zero gives itself.

$$2\sqrt{3}+9\sqrt{2}$$