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2\sqrt{3}+\sqrt{3}\sqrt{6}
Use the distributive property to multiply \sqrt{3} by 2+\sqrt{6}.
2\sqrt{3}+\sqrt{3}\sqrt{3}\sqrt{2}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
2\sqrt{3}+3\sqrt{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.