Solve sqrt{3}+2x=1/4+1/2

$$\sqrt{ 3 } +2x= \frac{ 1 }{ 4 } + \frac{ 1 }{ 2 }$$

Solve for x

$$x=-\frac{\sqrt{3}}{2}+\frac{3}{8}\approx -0.491025404$$

Steps for Solving Linear Equation

Least common multiple of 4 and 2 is 4. Convert \frac{1}{4} and \frac{1}{2} to fractions with denominator 4.

$$\sqrt{3}+2x=\frac{1}{4}+\frac{2}{4}$$

Since \frac{1}{4} and \frac{2}{4} have the same denominator, add them by adding their numerators.

$$\sqrt{3}+2x=\frac{1+2}{4}$$

Add 1 and 2 to get 3.

$$\sqrt{3}+2x=\frac{3}{4}$$

Subtract \sqrt{3} from both sides.

$$2x=\frac{3}{4}-\sqrt{3}$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\frac{3}{4}-\sqrt{3}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\frac{3}{4}-\sqrt{3}}{2}$$

Divide \frac{3}{4}-\sqrt{3} by 2.

$$x=-\frac{\sqrt{3}}{2}+\frac{3}{8}$$