Solve for x
x = \frac{19}{2} = 9\frac{1}{2} = 9.5
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2x-3=16
Square both sides of the equation.
2x-3-\left(-3\right)=16-\left(-3\right)
Add 3 to both sides of the equation.
2x=16-\left(-3\right)
Subtracting -3 from itself leaves 0.
2x=19
Subtract -3 from 16.
\frac{2x}{2}=\frac{19}{2}
Divide both sides by 2.
x=\frac{19}{2}
Dividing by 2 undoes the multiplication by 2.
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Limits
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