Solve sqrt{243}-sqrt{27}

$$\sqrt{ 243 } - \sqrt{ 27 }$$

Evaluate

$$6\sqrt{3}\approx 10.392304845$$

Solution Steps

Factor 243=9^{2}\times 3. Rewrite the square root of the product \sqrt{9^{2}\times 3} as the product of square roots \sqrt{9^{2}}\sqrt{3}. Take the square root of 9^{2}.

$$9\sqrt{3}-\sqrt{27}$$

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$9\sqrt{3}-3\sqrt{3}$$

Combine 9\sqrt{3} and -3\sqrt{3} to get 6\sqrt{3}.

$$6\sqrt{3}$$